Question

Solve x-y+z=2
2x+3y-4z=-4
3x+y+z=8
By using determinant method

Answer 1

Answer

x+y+2z=4

2x+2y+4z=8

3x+3y+6z=12

By determinant method:

⎝

⎜

⎜

⎛

1

2

3

1

2

3

2

4

6

⎠

⎟

⎟

⎞

×

⎝

⎜

⎜

⎛

x

y

z

⎠

⎟

⎟

⎞

=

⎝

⎜

⎜

⎛

4

8

12

⎠

⎟

⎟

⎞

D=

∣

∣

∣

∣

∣

∣

∣

∣

1

2

3

1

2

3

2

4

6

∣

∣

∣

∣

∣

∣

∣

∣

=0

Similarly, D

1

,D

2

,D

3

=0

As they all are 0 the set of equations will have infinite solutions.

We can consider x and y as free variables... x=α;y=β

Thus, the solution set is (α,β,

2

4−α−β

)

Answer 2

Step-by-step explanation:

please step by step explanation