solve x, y, z and t which is given in the image
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Answer:
T=90°(The diagonals bisects at 90°)
TQR+QTR+TRQ=180 (SUM OF ANGLES OF TRIANGLE)
60+90+Y=180
Y=30
PQT=TQR=30 (DIAGONALS BISECTS THE ANGLES)
PQT+QTP+TPQ=180
60+90+X=180
X=30
TRQ=TRS=30(DIAGONALS BIS.........)
TRS+RTS+TSR=180 (SUM OF......)
30+90+Z=180
Z=60
GIVEN,
PR=10cm
QS=24cm
PT=TR=5cm(AS DIAGONALS BISECTS EACH OTHER)
QT=TS=12cm (AS DIAGONALS.......)
SIN30°=P/H=1/2
THEREFORE,
PT/PS=1/2
5/PS=1/2
1/PS=1/10
PS=10cm
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