Math, asked by Debosreeta, 1 year ago

Solve x,y,z : x+y+z=9 , 2y-z=2 , z-x=2

Answers

Answered by mansi44
1
z-x=2
z=2+x put in eq 2
2y-z=2
2y-2-x=2
y=2+2+x/2 put in eq1
x+y+z=9
x+(4+x/2)+(2+x)=9
2x+(4+x)+4+2x=18
5x+8=18
5x=10
x=2
y=3
z=4
Answered by snehitha2
1
Hi friend!!

z - x = 2

→ x = z - 2

2y - z = 2

2y = z + 2

→ y = (z+2)/2

Put values of x and y in {x+y+z=9}

z-2 + (z+2)/2 + z = 9

2z + (z+2)/2 - 2= 9

{4z+z+2)/2 = 9+2

5z+2 = 11(2)

5z = 22-2

5z = 20

z = 20/5 = 4

x = z-2 = 4-2 = 2

y = (z+2)/2 = (4+2)/2 = 6/2 = 3

Therefore, x = 2 and y = 3 and z = 4

Hope it helps..
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