Solve x,y,z : x+y+z=9 , 2y-z=2 , z-x=2
Answers
Answered by
1
z-x=2
z=2+x put in eq 2
2y-z=2
2y-2-x=2
y=2+2+x/2 put in eq1
x+y+z=9
x+(4+x/2)+(2+x)=9
2x+(4+x)+4+2x=18
5x+8=18
5x=10
x=2
y=3
z=4
z=2+x put in eq 2
2y-z=2
2y-2-x=2
y=2+2+x/2 put in eq1
x+y+z=9
x+(4+x/2)+(2+x)=9
2x+(4+x)+4+2x=18
5x+8=18
5x=10
x=2
y=3
z=4
Answered by
1
Hi friend!!
z - x = 2
→ x = z - 2
2y - z = 2
2y = z + 2
→ y = (z+2)/2
Put values of x and y in {x+y+z=9}
z-2 + (z+2)/2 + z = 9
2z + (z+2)/2 - 2= 9
{4z+z+2)/2 = 9+2
5z+2 = 11(2)
5z = 22-2
5z = 20
z = 20/5 = 4
x = z-2 = 4-2 = 2
y = (z+2)/2 = (4+2)/2 = 6/2 = 3
Therefore, x = 2 and y = 3 and z = 4
Hope it helps..
z - x = 2
→ x = z - 2
2y - z = 2
2y = z + 2
→ y = (z+2)/2
Put values of x and y in {x+y+z=9}
z-2 + (z+2)/2 + z = 9
2z + (z+2)/2 - 2= 9
{4z+z+2)/2 = 9+2
5z+2 = 11(2)
5z = 22-2
5z = 20
z = 20/5 = 4
x = z-2 = 4-2 = 2
y = (z+2)/2 = (4+2)/2 = 6/2 = 3
Therefore, x = 2 and y = 3 and z = 4
Hope it helps..
Similar questions