Question

solve ..x2 +12x-20/3x-5=x2 +8x+12/2x+3​

Answer 1

Answer:

x2-10x-60=0

Step-by-step explanation:

(x2 +12x+20)/(3x-5) = (x2 +8x+12)/(2x+3)

(x+2)(x+10)/(3x-5) = (x+2)(x+6)/(2x+3)

Cancelling (x+2) from both the sides, we get

(x+10)/(3x-5) = (x+6)/(2x+3)

Cross multiplying

(x+10)(2x+3)  = (x+6)(3x-5)

2x2+23x+30 = 3x2+13x-30

x2-10x-60=0

​

Answer 2

Answer:

$\boxed{\mathsf \red{ \frac{ {x}^{2} + 12x - 20 }{3x - 5} = \frac{ {x}^{2} + 8x + 12 }{2x + 3} }} \\ \\ \mathsf{(2x + 3).( {x}^{2} + 12x - 20) \: = \: (3x - 5).( {x}^{2} + 8x + 12)} \\ \\ \mathsf{2 {x}^{3} + 27 {x}^{2} - 4x - 60 = 3 {x}^{3} + 19 {x}^{2} - 4x - 60 } \\ \\ \mathsf{27 {x}^{2} - 19 {x}^{2} = 3 {x}^{3} - 2 {x}^{3} } \\ \\ \mathsf{8 {x}^{2} = {x}^{3} } \\ \\ \boxed{ \mathsf{x = 8}}$

$\mathsf{}$

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