Math, asked by anayagawali24, 6 days ago

solve: x² + 12x - 96=0​

Answers

Answered by Sundaze77
2

Simplifying

x2 + 12x + -96 = 0

Reorder the terms:

-96 + 12x + x2 = 0

Solving

-96 + 12x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '96' to each side of the equation.

-96 + 12x + 96 + x2 = 0 + 96

Reorder the terms:

-96 + 96 + 12x + x2 = 0 + 96

Combine like terms: -96 + 96 = 0

0 + 12x + x2 = 0 + 96

12x + x2 = 0 + 96

Combine like terms: 0 + 96 = 96

12x + x2 = 96

The x term is 12x. Take half its coefficient (6).

Square it (36) and add it to both sides.

Add '36' to each side of the equation.

12x + 36 + x2 = 96 + 36

Reorder the terms:

36 + 12x + x2 = 96 + 36

Combine like terms: 96 + 36 = 132

36 + 12x + x2 = 132

Factor a perfect square on the left side:

(x + 6)(x + 6) = 132

Calculate the square root of the right side: 11.489125293

Break this problem into two subproblems by setting

(x + 6) equal to 11.489125293 and -11.489125293.

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