Question

solve x²-15x+26=0..
explain​

Answer 1

Answer:

Hope this will help you

Answer 2

As per given

${x}^{2} - 15x + 26$

The simple step is

Do the product of first and third term

and split the middle term in its form

For Example

$- x {}^{2} \times - 26 = 26 {x}^{2} \\ so \: split \: the \: middle \: term \: to \: get \: the \\ product \: as \: 26 {x}^{2}$

i.e

-13x and -2x

$= > {x}^{2} - 13x - 2x + 26 \\ = > x(x - 13) - 2(x - 13) \\ = > (x - 2)(x - 13)$

So factors are 2 and 13.