Solve x²-(√2+1)x +√2 by completing the square method with multiplication method.....Plzz tell fast
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Step-by-step explanation:
let √2= a and 1=b
As the polynomial p(x) is in the form of
p(x)= x^2 - (a+b)x+ ab = (x-a)(x-b)
therefore, p(x)= x^2 - (√2+1)x + √2
p(x) = (x-√2)(x-1) =0
So, x=√2 and x=1
the zeros of the polynomial p(x) :- √2 & 1
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