Question

Solve: X2 + 2 √2x -6 =0 , by factorization method.

Answer 1

x²+(3√2-√2)x-6=0,

x²+3√2x-√2x-6=0,

x(x+3√2)-√2(x+3√2)=0,

(x+3√2)(x-√2)=0

Answer 2

Answer:

x=$\sqrt{2}$ and x=-3$\sqrt{2}$

Step-by-step explanation:

Step-1. Expanding the middle term 2$\sqrt{2}$ you will be getting the following:

$x^{2}$+(3$\sqrt{2}$-$\sqrt{2}$)x-6=0.

Step-2. Expanding (3$\sqrt{2}$-$\sqrt{2}$)x you will obtain:

$x^{2}$+3$\sqrt{2}$x-$\sqrt{2}$x-6=0

Step-3. Now expanding again the middle term you will get the following:

x(x+3$\sqrt{2}$)-$\sqrt{2}$(x+3$\sqrt{2}$)=0

Step-4. Now as you can see that we got two common terms:

(x+3$\sqrt{2}$) and (x-$\sqrt{2}$).

Step-5. So, now we will get the value of x as following:

x+3$\sqrt{2}$=0; x= -3$\sqrt{2}$

x-$\sqrt{2}$=0; x= $\sqrt{2}$

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