solve x2-2√5x +3 by middle term
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Step-by-step explanation:
x2-2√5x +3
= x² -{(√5 +√2) + (√5 - √2)}x + (√5 - √2)(√5 + √2)
= x² - (√5 + √2)x - (√5 -√2)x + (√5 + √2)(√5 - √2)
= x[x - √5 - √2] - (√5 - √2)[x - √5 - √2]
= [x - √5 - √2][x - √5 + √2]
Hence, x = √5 ± √2 are the zeros of given expression
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