Solve: x²+250x-7500000.
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These are the most accurate values of x,if the equation is x²+250x-7500000=0
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thanx kavya
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quadratic eq : x² + 250 x - 7500, 000 = 0
discriminant: b² - 4ac = √(250² + 4*1*7500,000)
= 250 √(1 + 16*30) = 250*√481
x = [- 250 + 250√481]/2 or [-250 - 250√481]/2
= 125(√481 - 1) or -125(√481 +1)
= 125 [√(484 - 3) -1 ] or -125 * [√(484 -3) + 1 ]
≈ 125 [ 22 √(1 - 3/484) - 1] or -125 [ 22 √(1 -3/484) + 1 ]
≈ 125 [ 22 (1 - 3/968) - 1 ] or -125 [ 22 (1 - 3/968) + 1]
≈ 125 [ 22 - 3/44 - 1] or -125 [ 22 - 3/44 + 1 ]
≈ 125 * 921/44 or - 125 * 1011/44
≈ 921000/352 or - 1011000/352
near exact solution: x = 2, 616.464 or - 2, 866.464
discriminant: b² - 4ac = √(250² + 4*1*7500,000)
= 250 √(1 + 16*30) = 250*√481
x = [- 250 + 250√481]/2 or [-250 - 250√481]/2
= 125(√481 - 1) or -125(√481 +1)
= 125 [√(484 - 3) -1 ] or -125 * [√(484 -3) + 1 ]
≈ 125 [ 22 √(1 - 3/484) - 1] or -125 [ 22 √(1 -3/484) + 1 ]
≈ 125 [ 22 (1 - 3/968) - 1 ] or -125 [ 22 (1 - 3/968) + 1]
≈ 125 [ 22 - 3/44 - 1] or -125 [ 22 - 3/44 + 1 ]
≈ 125 * 921/44 or - 125 * 1011/44
≈ 921000/352 or - 1011000/352
near exact solution: x = 2, 616.464 or - 2, 866.464
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