Question

solve: x²×2y⅖×23-ab²+b³​

Answer 1

Answer:

3x2

−23x+40=03x2

−15x−8x+40=0, split the middle term

−15x)+(−8x+40) group the terms

3x(x−5)−8(x−5)=0

(x−5)(3x−8)=0, factor

x−5=0 or 3x−8=0, zero product property

x=5 or x= 38