Question

) Solve (x² – 2y2)dx + xy dy = 0 .​

Answer 1

Answer:

= x²-2y²+ y = 0

Step-by-step explanation:

(x²-2y²)dx + xy•dy = 0

= (x²-2y²)dx + y(dx) = 0

= dx { (x²-2y²) + y } = 0

= dx { (x²-(√2y)²) + y } = 0

= dx { (x-√2y) (x+√2y) + y } = 0

= (x-√2y) (x+√2y) + y = 0

= x²-2y²+ y = 0

Or

= dx = 0

Hope this help you

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