Math, asked by Anonymous, 10 months ago

Solve x²-4|x|+3<0.............​

Answers

Answered by Anonymous
1

hence there is no real sol.

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Answered by Anonymous
2

Answer:

Two different ways of writing the answer (both mean the same thing):

  • x ∈ (-3, -1) ∪ (1, 3)
  • -3 < x < -1  or  1 < x < 3

Step-by-step explanation:

    x² - 4|x| + 3 < 0

⇔ x² - 4|x| + 4 < 1

⇔ (|x| - 2)² < 1

⇔ | |x| - 2 | < 1

⇔ -1 < |x| - 2 < 1

⇔  1 < |x| < 3

⇔ -3 < x < -1  or  1 < x < 3

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