Solve x²-4|x|+3<0.............
Answers
Answered by
1
hence there is no real sol.
Attachments:
Answered by
2
Answer:
Two different ways of writing the answer (both mean the same thing):
- x ∈ (-3, -1) ∪ (1, 3)
- -3 < x < -1 or 1 < x < 3
Step-by-step explanation:
x² - 4|x| + 3 < 0
⇔ x² - 4|x| + 4 < 1
⇔ (|x| - 2)² < 1
⇔ | |x| - 2 | < 1
⇔ -1 < |x| - 2 < 1
⇔ 1 < |x| < 3
⇔ -3 < x < -1 or 1 < x < 3
Similar questions