solve x²+4ix-5=0 where i=√-1
Answers
Answer:STEPS USING THE QUADRATIC FORMULA
x
2
−4ix−5=0
All equations of the form ax
2
+bx+c=0 can be solved using the quadratic formula:
2a
−b±
b
2
−4ac
. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x
2
−4ix−5=0
This equation is in standard form: ax
2
+bx+c=0. Substitute 1 for a, −4i for b, and −5 for c in the quadratic formula,
2a
−b±
b
2
−4ac
.
x=
2
4i±
(−4i)
2
−4(−5)
Square −4i.
x=
2
4i±
−16−4(−5)
Multiply −4 times −5.
x=
2
4i±
−16+20
Add −16 to 20.
x=
2
4i±
4
Take the square root of 4.
x=
2
4i±2
Now solve the equation x=
2
4i±2
when ± is plus. Add 4i to 2.
x=
2
2+4i
Divide 2+4i by 2.
x=1+2i
Now solve the equation x=
2
4i±2
when ± is minus. Subtract 2 from 4i.
x=
2
−2+4i
Divide −2+4i by 2.
x=−1+2i
The equation is now solved.
x=1+2i
x=−1+2i
Step-by-step explanation:
Answer:
Hii ARMY
HOW ARE YOU DOING
