Question

Solve : x2 – 4x + 3 = 0​

Answer 1

Given: $x^2 - 4x + 3 = 0$

We have to solve the above equation.

• For this, we will split the middle term such that the product of the numbers is the last term and the sum or difference of those numbers is the middle term.
• Here, $-4x$is the middle term and $3$is the last term.

We are solving in the following way:

We have,

$x^2 - 4x + 3 = 0$

Now, the product of 3 is$3\times 1=3$ and$-3x-1x=-4x$

So,

$=>x^2-3x-1x+3\\=>x(x-3)-1(x-3)\\=>(x-1)(x-3)$

Then,

$=>x-1=0\\=>x=1\\or\\=>x-3=0\\=>x=3$

Hence, we get,

$x=3\ or \ x=1$

Answer 2

$\sf \: {x}^{2} - 4x + 3 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \: {x}^{2} - 3x - x + 3 = 0 \: \: \: \: \: \\ \\ \sf \: x(x - 3) - 1(x - 3) = 0 \\ \\ \sf \: (x - 1)(x - 3) = 0 \: \: \: \: \: \: \: \: \: \\ \\ \sf \: x = 1 \: \: \: or \: \: \: x = 3 \: \: \: \: \: \: \: \: \: \:$