Question

solve x²+4x-5=0 by completing square method.​

Answer 1

Answer:

x^2+4x-5=0

x^2+5x-x-5

x(x+5)-1(x+5)

(x-1)(x+5)

x=1or x=-5

Answer 2

Step-by-step explanation:

${x}^{2} + 2(2)(x) + 4 - 4 - 5 = 0 \\ (x - 2) {}^{2} = 9 \\ x - 2 = \pm \: 3 \\ x = 5 \: and \: - 1$