Solve: x²+5।x।+6 Here, |x| is modulas x Pls answer.
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EXPLANATION.
⇒ x² + 5|x| + 6.
As we know that,
Case = 1.
When x > 0.
⇒ x² + 5x + 6 = 0.
Factorizes the equation into middle term splits, we get.
⇒ x² + 3x + 2x + 6 = 0.
⇒ x(x + 3) + 2(x + 3) = 0.
⇒ (x + 2)(x + 3) = 0.
⇒ x = - 2 & x = - 3.
Case = 2.
When x < 0.
⇒ x² - 5x + 6 = 0.
Factorizes the equation into middle term splits, we get.
⇒ x² - 3x - 2x + 6 = 0.
⇒ x(x - 3) - 2(x - 3) = 0.
⇒ (x - 2)(x - 3) = 0.
⇒ x = 2 & x = 3.
MORE INFORMATION.
Conjugate roots.
(1) = If D < 0.
One roots = α + iβ.
Other roots = α - iβ.
(2) = If D > 0.
One roots = α + √β.
Other roots = α - √β.
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