Solve : x2- 5i x-6 = 0
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Answer:
Step-by-step explanation:
Here a=1, b=−5i (complex number) and c=−6
α= 2a−b+ b 2 −4ac
and β= 2a−b− b 2 −4ac
α= 2×1(−(−5i)+ (−5i) 2 −4×1×(−6))
=(5i+i)/2
=3i
β= 2×1−(−5i)− (−5i) 2 −4×1×(−6)
=(5i−i)/2
=2i
So, the roots of the given equation are 3i and 2i.
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