Solve x² + 5x - 300 = 0.
Answers
Answered by
106
Method to find solution of a quadratic equation by factorisation:
To find the solution of a quadratic equation by factorization method we use following steps:
Write the given quadratic equation in standard form ax² + bx + c =0, and find the values of a, b and c.
Multiply a and c and split ac into prime factors. Then find two numbers p and q such that p-q = b (if Sign of c is negative -ve).
Write the constant b of ax² + bx + c =0, as (p-q) and then factorise it.
Equate each factor to zero and find the values of x.
SOLUTION:
GIVEN:
x² +5x -300 = 0
x² + 20x -15x -300= 0
x( x +20) -15(x +20)= 0
(x +20)(x- 15)= 0
(x +20)= 0 or (x- 15)= 0
x= -20 or x= 15
HOPE THIS WILL HELP YOU....
To find the solution of a quadratic equation by factorization method we use following steps:
Write the given quadratic equation in standard form ax² + bx + c =0, and find the values of a, b and c.
Multiply a and c and split ac into prime factors. Then find two numbers p and q such that p-q = b (if Sign of c is negative -ve).
Write the constant b of ax² + bx + c =0, as (p-q) and then factorise it.
Equate each factor to zero and find the values of x.
SOLUTION:
GIVEN:
x² +5x -300 = 0
x² + 20x -15x -300= 0
x( x +20) -15(x +20)= 0
(x +20)(x- 15)= 0
(x +20)= 0 or (x- 15)= 0
x= -20 or x= 15
HOPE THIS WILL HELP YOU....
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Answered by
34
x^2 + 5x - 300
x^2 + 20x - 15x - 300
x(x + 20) -15(x + 20)
(x + 20)(x - 15)
so,
x = - 20
and
x = 15
x^2 + 20x - 15x - 300
x(x + 20) -15(x + 20)
(x + 20)(x - 15)
so,
x = - 20
and
x = 15
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