Math, asked by nishmithav875, 2 months ago

solve x²-5x+6=0 by using quadratic formula​

Answers

Answered by veeresh1937
1

Step-by-step explanation:

Use the quadratic formula

=

±

2

4

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

5

+

6

=

0

x^{2}-5x+6=0

x2−5x+6=0

=

1

a={\color{#c92786}{1}}

a=1

=

5

b={\color{#e8710a}{-5}}

b=−5

=

6

c={\color{#129eaf}{6}}

c=6

=

(

5

)

±

(

5

)

2

4

1

6

2

1

Answered by sanju2363
1

 \rm \: Use \:  the \:  quadratic \:  formula \\ </p><p></p><p>=−±2−4√2 \\ </p><p></p><p>x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}} \\ </p><p></p><p>Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula. \\ </p><p></p><p></p><p></p><p>x^{2}-5x+6=0 \\ </p><p></p><p></p><p></p><p>a={\color{#c92786}{1}} \\  \\ </p><p></p><p></p><p></p><p>b={\color{#e8710a}{-5}} \\  \\ </p><p></p><p></p><p></p><p>c={\color{#129eaf}{6}} \\  \\ </p><p></p><p></p><p></p><p>x=\frac{-({\color{#e8710a}{-5}}) \pm \sqrt{({\color{#e8710a}{-5}})^{2}-4 \cdot {\color{#c92786}{1}} \cdot {\color{#129eaf}{6}}}}{2 \cdot {\color{#c92786}{1}}} \\  \\ </p><p></p><p></p><p></p><p>Simplify \\  \\ </p><p></p><p>Evaluate the exponent \\  \\ </p><p></p><p>Multiply the numbers \\  \\ </p><p></p><p>Subtract the numbers \\  \\ </p><p></p><p>Evaluate the square root \\  \\ </p><p></p><p>Multiply the numbers \\  \\ </p><p></p><p></p><p></p><p>x=\frac{5 \pm 1}{2} \\  \\ </p><p></p><p></p><p></p><p>Separate the equations \\  \\ </p><p></p><p>To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus. \\  \\ </p><p></p><p></p><p></p><p>x=\frac{5+1}{2} \\  \\ </p><p></p><p>=5−12 \\  \\ </p><p></p><p>x=\frac{5-1}{2} \\  \\ </p><p></p><p></p><p></p><p>Solve \\  \\ </p><p></p><p>Rearrange and isolate the variable to find each solution \\  \\ </p><p></p><p>=3 \\  \\ </p><p></p><p>x=3x=3 \\  \\ =2 \\  \\ x=2x=2 \\  \\ Solution \\  \\ =3 \\  \\ =2 \\  \\ </p><p></p><p>

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