solve x2- 6x + 5=0 using quadratic formula
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Formula is x =[ -b±√(b²-4ac)] / 2a
Here in our question,
a = 1 , b= -6 , c= 5
On substituting, we get,
x = [-(-6)±√(36-4(1)(5)] / 2
x = (6 ±√16)/2
x = (6+4)/2 or x= (6-4)/2
x = 5 or x = 1
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