Question

solve
x² -7x + 12 = 0
formula.
by
using quadratic​

Answer 1

Answer:

value of x = 4 or x = 3

Step-by-step explanation:

solution is in the above photo

Answer 2

Given to find the roots  of Quadratic equation x²-7x+12 by Quadratic formula:-

SOLUTION :-

The quadratic formula is

$x = \dfrac{-b\pm\:\sqrt{b^2-4ac} }{2a}$

So,

x²- 7x + 12 comparing with ax² +bx+c we get the value of a, b, c So,

• a= 1
• b = -7
• c = 12

Substituting the values we get

$x = \dfrac{-b\pm\:\sqrt{b^2-4ac} }{2a}$

$x = \dfrac{-(-7)\pm\sqrt{(-7)^2-4(1)(12)} }{2(1)}$

$x =\dfrac{7 \pm\sqrt{49-48} }{2}$

$x = \dfrac{7\pm\sqrt{1} }{2}$

$x=\dfrac{7\pm1}{2}$

$x =\dfrac{7+1}{2} and \dfrac{7-1}{2}$

$x =\dfrac{8}{2} \: and \:\dfrac{6}{2}$

$x = 4\:and \: 3$

So, the roots  of the given quadratic equation is 4 and 3

Verification :-

We got now the roots of the given equation hence if we substitute them it should be equal to 0

$x^2-7x+12=0$

At x = 4

$(4)^2- 7(4) +12=0$

$16-28+12=0$

$28-28=0$

$0=0$

L.H.S = R.H.S

$x^2-7x+12$

At x= 3

$(3)^2-7(3) +12 =0$

$9-21+12=0$

$21-21=0$

$0=0$

L.H.S = R.H.S

Verified!