Question

Solve x2 + 7x = 7 and give your answer correct to two decimal places.


Please help.

Answer 1

Answer:

0.175

Step-by-step explanation:

x²+7x=7

x²+7x-7=0

find the root of the quadratic equation

it is in form of ax²+bx+c=0

a=1 b=7 c=-7

x=[-b+/-(b²-4ac)^1/2]/2a (b²-4ac)^1/2= under root b²-4ac

x=[-7+(7²-(4×1×-7)^1/2]/2×1 or [-7-(7²-(4×1×-7)^1/2]/2×1]

x=[-7+(49-(-28))^1/2]/2 (-7+root under 63)/2

root under 63 =root under 9×root under 7

=3×root 7

root 7~2.45

(-7+3×2.45)/2=-7+7.35=0.35/2

x=0.175

Answer 2

Answer:

mark BRAINLIEST

Step-by-step explanation:

Given equation is x2+7x=7

⇒x2+7x−7=0

Using the quadratic formula, we get:

x=2×1−7±49+28

⇒x=2−7±77=0.89,−7.89

Thus, there are two values of x i.e 0.89 and −7.89 (correct up to two decimal places)