Question

Solve : x2 +8x + 4 = 0 quadratic equations..

Answer 1

Answer:

for the value of x in qe ax^2+bx+c=0 is

x=(-b+√(b^2-4ac)) /2a

x=(-8+√(8^2-4x1x4)) /2

x=(-8+√(64+16))/2

x=-8/2+√80/2=-4+4√5/2

x=-4+2√5 and -4-2√5