Question

Solve : x2 + 8x - 48 = 0 by factorisation​

Answer 1

$\huge\star\mathfrak\red{{Answer:-}}$

x2 + 8x - 48 = 0

x2 + 12x - 4x - 48 = 0

x (x + 12) - 4(x+ 12) = 0

(x+ 12) (x - 4)= 0

x+ 12 = 0 or x - 4 = 0

x = -12 or x = 4

Answer 2

Step-by-step explanation:

$x^2+12x-4x-48=0 \\ </p><p>x(x+12)-4 (x+12)=0 \\ </p><p>(x+12)(x+4)=0 \\ </p><p>(x+12) = 0 \: or \: (x+4) = 0 \\ </p><p>x= -4 \: or \: x = -12</p><p></p><p>$