Question

solve:
x²+9x+20=0
if u answer this I will make you as a brainlist
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\bold{\blue{\underline{\red{G}\pink{iv}\green{en}\purple{:-}}}}$

• x² + 9x + 20 = 0

$\bold{\blue{\underline{\red{Zeros}\pink{\:of\:}\green{\:the\:Quadratic\:equation}\purple{:-}}}}$

• Zeros of the quadratic equation is the value of the variable for which when replaced in the quadratic equations the value for the quadratic equation changes to zero.

$\bold{\blue{\underline{\red{General}\pink{\:form \:of }\green{\:Quadratic\:equation}\purple{:-}}}}$

• ax² + bx + c = 0

$\bold{\blue{\underline{\red{Q}\pink{uest}\green{ion}\purple{:-}}}}$

• To find the zeros of the quadratic equation .

$\bold{\blue{\underline{\red{S}\pink{olut}\green{ion}\purple{:-}}}}$

• x² + 9x + 20 = 0
• a = 1
• b = 9
• c = 20
• Quadratic formula = $\bold{\frac{-b\: \pm\:{\sqrt{b^{2}\:-\:4ac} }}{2a}}$  

• x = $\bold{\frac{-9\: \pm\:{\sqrt{9^{2}\:-\:4(1)(20)} }}{2(1)}}$

• x = $\bold{\frac{-9\: \pm\:{\sqrt{81\:-\:80} }}{2}}$  

• x = $\bold{\frac{-9\: \pm\:{\sqrt{1} }}{2}}$     ∵ any √1 is 1

• x = $\bold{\frac{-9\: \pm\:{1}}{2}}$

• x = $\bold{\frac{-9\ -\:{1}}{2}}$

• x = $\bold{\frac{-10}{2}}$

     $\bold{\boxed{\green{x\: =\: -5}}}$

• x = $\bold{\frac{-9\ +\:{1}}{2}}$

• x = $\bold{\frac{-8}{2}}$

     $\bold{\boxed{\green{x\: =\: -4}}}$