Question

solve
x²+x+1=0
pls solve this quadratic equation.​

Answer 1

Solution of quadratic equation( ax2+bx+c=0) is given by -

x=−b±b2−4ac√2a . . . (1)

Here, a = 1, b = 1 and c = 1 (x2+x+1=0)

Just put the value of a, b and c in eq(1),

x=−1±12−4∗1∗1√2∗1

x=−1±−3√2

This is shows its have only imaginary roots.

As i=−1−−−√.

x=−1±i3√2

So two roots are,

x=−1+i3√2 and x=−1−i3√2.

Hope it helps you !

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Answer 2

Answer:

x²+x+1=0

Step-by-step explanation:

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