Question

Solve:
x² + x - 12 = 0​

Answer 1

Answer:

$x² + x - 12 = 0 \\ {x}^{2} + 4x - 3x - 12 = 0 \\ x(x + 4) - 3(x + 4) = 0 \\ (x + 4)(x - 3) = 0 \\ x = 3, - 4$

Answer 2

Step-by-step explanation:

${x}^{2} + x - 12 \\ = {x}^{2} - 4x + 3x - 12 \\ = x(x - 4) + 3(x - 4) \\ = (x + 3)(x - 4) \\ x = - 3 \: and \: 4$

hope this helps you.