Math, asked by garima0845919, 9 months ago

solve x²-x-2>0
plz help me to solve out this question​

Answers

Answered by dhanasri19112006
1

Answer:

...-6,-5,-4,-3,-2,-1,0,1

Step-by-step explanation:

x square -x-2>0

x-2>0

x-0<2

x<2

...-6,-5,-4,-3,-2,-1,0,1

Answered by Thatsomeone
6

Step-by-step explanation:

 \sf {x}^{2} - x - 2 &gt; 0 \\ \\ \sf {x}^{2}- 2x + x - 2 &gt; 0 \\ \\ \sf x(x-2) + 1(x-2) &gt;0 \\ \\ \sf (x-2)(x+1)&gt;0 \\ \\ \sf By\:wavy\:curve\: method \\ \\ \sf x = (-∞ , - 1 ) U ( 2,∞)

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