Solve : (x²-x)² + (x²-x) + 4 = 0
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How do you solve equation 4 (x² -x) ²-11 (x²-x) +6=0 for x?
Put s=(x^2 - x) and Rewrite the above equation.
4s^2 - 112 +6=0
This is a quadratic equation .
s={11 +/- ✔(121 -4*4*6)}/2*8
s=2
s=3/4
Substituting s value (s=2)
x^2 -x = 2
x^2 - x - 2=0 ( A quadratic equation again )
(x+1)(x -2 )= 0
x= - 1 Or x=2 ————-(i)
Substituting s value (s=3/4)
x^2 - x =3/4
Or x^2 - x - 3/4= 0 (Again a quadratic eqn.)
Or 4x^2 - 4x - 3 =0
x=[4 +/- ✔{(16–4*4*(-3)}]/2*4
x=5/4 Or x= - 1/4 ————-(ii)
Combining (i)&(ii) values, we get
x={5/2 ,2, (- 1/4), (-1) □ANSWER.
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