Question

solve x²-x/5+1/100=0 by discriminant method​

Answer 1

Answer:

Answer: It has two equal roots as follows:

x=\frac{1}{10},\ and\ \frac{1}{10}x=

10

1

, and

10

1

Step-by-step explanation:

Since we have given that

\begin{gathered}x^2-\frac{x}{5}+\frac{1}{100}=0\\\\100x^2-20x+1=0\\\end{gathered}

x

2

−

5

x

+

100

1

=0

100x

2

−20x+1=0

We need to find the roots of the quadratic equation:

\begin{gathered}x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{20\pm\sqrt{400-4\times 100\times 1}}{2\times 100}\\\\x=\frac{20-0}{200}\\\\x=\frac{1}{10},\frac{1}{10}\end{gathered}

x=

2a

−b±

b

2

−4ac

x=

2×100

20±

400−4×100×1

x=

200

20−0

x=

10

1

,

10

1

Hence, it has two equal roots as follows:

x=\frac{1}{10},\ and\ \frac{1}{10}x=

10

1

, and

10

1