solve : x² - x-a(a+1)=0
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Given: x2 – x –a(a + 1) = 0
⇒ x2 – x – a2 – a = 0
⇒ (x2 – a2 ) – (x + a) = 0
⇒ (x + a)(x – a) – (x + a) = 0 [∵ a2 – b2 = (a + b)(a - b) ]
⇒ (x + a)[(x – a) – 1)] = 0
⇒ (x + a) = 0 or (x – a) – 1 = 0
⇒ x = – a or x = (a + 1)
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