Solve: x2 + x + y = log x sin ( log x)
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Answer:
y=sin(logx)
dx
dY = x
cos(logx)
dx 2d 2y= x 2−sin(logx)−cos(logx)
∴x 2
dx 2
d 2
y+x dx
dd+y=−sin(logx)−cos(logx)+cos(logx)+sin(logx)
=0proved.ans
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