Math, asked by deepondeb24, 6 months ago

Solve- x²+y²=13 and xy= 6​

Answers

Answered by deep25413
0

Answer:

we use the identity (x+y)^2= x^2+2xy+y^2

since we have all the values beforehand, we will start putting the values

(x+y)^2= 13 + 2(6)

(x+y)^2= 25

(x+y)= root25

x+y=5

I hope this helps u!!

Answered by 04517
0

Answer:

x=3   y=2

Step-by-step explanation:

(x+y)² = x²+y²+2xy

(x+y)² = 13+2(6) = 13+12 = 25

x+y = 5

(x-y)² = x²+y²-2xy

(x-y)² = 13-12 = 1

x-y = 1

on solving,

2x=6

x=3   y=2

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