Solve- x²+y²=13 and xy= 6
Answers
Answered by
0
Answer:
we use the identity (x+y)^2= x^2+2xy+y^2
since we have all the values beforehand, we will start putting the values
(x+y)^2= 13 + 2(6)
(x+y)^2= 25
(x+y)= root25
x+y=5
I hope this helps u!!
Answered by
0
Answer:
x=3 y=2
Step-by-step explanation:
(x+y)² = x²+y²+2xy
(x+y)² = 13+2(6) = 13+12 = 25
x+y = 5
(x-y)² = x²+y²-2xy
(x-y)² = 13-12 = 1
x-y = 1
on solving,
2x=6
x=3 y=2
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