solve (x2+y2) dx-2xydy=0
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Given, (x^2 + y^2) dx - 2xy dy = 0 (x^2 + y^2) dx = 2xydy dydx = x^2 + y^2
Step-by-step explanation:
Use. x=u+v. y=u−v. (substitution of new variables u=(x+y)/2
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Answer to solve this homogeneous differential equation: (x^2+y^2)d x-2 x y d y=0 find the general solution of the following differential
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