Question

Solve (x2D2 + 4xD + 2)y = 0​

Answer 1

Answer:

The solutions are

$x=\frac{\sqrt{-4 D-2}}{D}, x=-\frac{\sqrt{-4 D-2}}{D}, y=0 ; \quad D \neq 0$

Step-by-step explanation:

Step 1: You know that if the product is 0, then one or both of the elements must also be 0, thanks to the Principle of Zero Products. Set each variable to 0. Work out each equation. You may test these answers by individually inserting them into the original equation, (x + 4)(x - 3).

$\left(x^2 D^2+4 D+2\right) y=0$

Using the Zero Factor Principle: If a b=0 then a=0 or b=0

$x^2 D^2+4 D+2=0 \text { or } y=0$

Step 2:According to the Zero Product Property, if ab=0, then either a=0 or b=0 (or both). If and only if one or more of the components in a product are zero, the product is zero. This is very helpful when attempting to solve quadratic problems.

Solve $x^2 D^2+4 D+2=0: \quad x=\frac{\sqrt{-4 D-2}}{D}, x=-\frac{\sqrt{-4 D-2}}{D} ; \quad D \neq 0$

y=0

The solutions are

$x=\frac{\sqrt{-4 D-2}}{D}, x=-\frac{\sqrt{-4 D-2}}{D}, y=0 ; \quad D \neq 0$

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