solve x³-9x²+24x-20=0
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x3 - 9x2 + 24x - 20 = (x-2)(x-2)(x-5)
f(x)= x3 - 9x2 + 24x - 20
By the rational root theorem, any rational zeroes of f(x) are expressible in the form p/q for integers p, q with p a divisor of the constant term 20 and q a divisor of the coefficient 1 of the leading term .
That means that the only possible rational zeroes are:
+1, +2, +4, +5, +10, +20
trying each in turn, we find:
f(2) = 8 - 9(4) + 24(2) - 20 = 8 - 36 + 48 - 20 = 0
so x = 2 is a zero and (x - 2) a factor:
x3 - 9x2 + 24x - 20 = (x - 2)(x2 - 7x + 10)
Note that 7 = 2 + 5 and 10 = 2.5
so we find:
x2 - 7x + 10 = (x - 2)(x - 5)
putting it all together:
x3 - 9x2 + 24x -20 = (x - 2) (x - 2) (x - 5)
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