Math, asked by vibhutisingh2312, 1 month ago

Solve:
x³+x+4/x=x(x+3);x not belong to 0.​

Answers

Answered by fundjgol
1

Answer:

x³+x+4/x=x²+3x

x³+x+4-3x=x(x²)

x³+x-3x-x³=-4

x-3x=-4

-2x=-4

x=-4/-2

x=2

Answered by nishantmahanur7
2

Answer:

x^3+x+4/x= x^2 + 3x

x^3+x+4-3x= x(x^2)

x^3+x-3x-x^3= -4

x-3x= -4

-2x= -4

x= -4/-2

x= 2

* Hope it will help you.☺

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