Question

Solve x⁴-13x²+42=0 ​

Answer 1

Answer:

the p(x) = 0

let x = 0

answer is 42

Answer 2

Answer:

Hey there

${x}^{4} - 13 {x}^{2} + 42 = 0 \\ {x}^{4} - 7 {x}^{2} - 6 {x}^{2} + 42 = 0 \\ {x}^{2} ( {x}^{2} - 7) - 6( {x}^{2} - 7) = 0 \\ ( {x}^{2} - 6)( {x}^{2} - 7) = 0 \\ {x}^{2} = 6 \\ x = \sqrt{6} \\ or \\ {x}^{2} = 7 \\ x = \sqrt{7}$

Hope it helps you

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