solve x⁴+y⁴ if x+y=8,xy=12
Answers
Answered by
1
x = 6
y = 2
6^{4} + 2^{4} = 1296 + 16 =1312
y = 2
6^{4} + 2^{4} = 1296 + 16 =1312
Answered by
1
by trial and eror method we get x=2,y=6 or x=6 ,y=2 in both the cases we get same answer since it is addition.2^4=16 and 6^4=1296,1296+16=1312
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