Solve xlog(base 3)x=81x^3
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Given: x^ ( log(base 3)x ) = 81 x^3
To find: Solve the above question.
Solution:
- As we have given both sides x, and the rest terms in the powers, so lets take log with base 3 on both sides, we get:
log (base 3) {x^ ( log(base 3)x ) }= log( base 3) 81 x^3
{log (base 3) x }^2 = 3 log( base 3) x + 4{ log( base 3) 3}
{log (base 3) x }^2 = 3 log( base 3) x + 4
- Now, replace log (base 3) x by y, we get:
y^2 = 3y + 4
y^2 - 3y - 4 = 0
- simplifying it, we get:
(y-4) x (y+1) = 0
y = 4, -1
- Now replace y with log (base 3) x
log (base 3) x = 4, log (base 3) x = -1
x = 3^4 , 1/3
Answer:
So the value of x is 3^4 , 1/3.
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