Question

solve xsquare-9=0 in factorisation method

Answer 1

${x}^{2} - 9 = 0 \\ = > {(x)}^{2} - {(3)}^{2} = 0 \\ = > (x - 3)(x + 3) = 0$

So,

x = 3

or,

x = -3

Answer 2

Answer:

given x² - 9 = 0

=> (x + 9)(x - 9) = 0 [ a² - b² = (a + b)(a - b) ]

=> x + 9 = 0 or x = -9

=> x - 9 = 0 or x = +9