Math, asked by sakshaysahil, 4 months ago

solve (xy-2y²)dx-(x²-3xy)dy=0​

Answers

Answered by madhupathak2
2

Answer:

Simplifying

(xy + -2y2) * dx + -1(x2 + -3xy) * dy = 0

Reorder the terms for easier multiplication:

dx(xy + -2y2) + -1(x2 + -3xy) * dy = 0

(xy * dx + -2y2 * dx) + -1(x2 + -3xy) * dy = 0

Reorder the terms:

(-2dxy2 + dx2y) + -1(x2 + -3xy) * dy = 0

(-2dxy2 + dx2y) + -1(x2 + -3xy) * dy = 0

Reorder the terms:

-2dxy2 + dx2y + -1(-3xy + x2) * dy = 0

Reorder the terms for easier multiplication:

-2dxy2 + dx2y + -1dy(-3xy + x2) = 0

-2dxy2 + dx2y + (-3xy * -1dy + x2 * -1dy) = 0

-2dxy2 + dx2y + (3dxy2 + -1dx2y) = 0

Reorder the terms:

-2dxy2 + 3dxy2 + dx2y + -1dx2y = 0

Combine like terms: -2dxy2 + 3dxy2 = 1dxy2

1dxy2 + dx2y + -1dx2y = 0

Combine like terms: dx2y + -1dx2y = 0

1dxy2 + 0 = 0

1dxy2 = 0

Solving

1dxy2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '1'.

dxy2 = 0

Simplifying

dxy2 = 0

The solution to this equation could not be determined.

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Step-by-step explanation:

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