Question

solve:
(y+1)-(2y+3)/3-2y=1/4​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given equation is [(y+1)-(2y+3)]/(3-2y) = 1/4

=> (y+1-2y-3)/(3-2y) = 1/4

=> (-y-2)/(3-2y) = 1/4

On applying cross multiplication then

=> 4(-y-2) = 1(3-2y)

=> -4y-8 = 3-2y

=> -4y+2y = 3+8

=> -2y = 11

=> y = 11/-2

Therefore y = -11/2

The value of y for the given problem is -11/2