Question

Solve √y+1 + √2y-5 = 3

Answer 1

Answer:

3

Step-by-step explanation:

+1✓2y-5=3. +3y-5=3. +3. 3

Answer 2

The solution of the radical equation is y = 3

Step-by-step explanation:

The given equation is

$\sqrt{y+1}+\sqrt{2y-5}=3$

Subtract $\sqrt{2y-5}$ to both sides

$\sqrt{y+1}=3-\sqrt{2y-5}$

Squaring both sides

$y+1=2y+4-6\sqrt{2y-5}$

On simplifying, we get

$-y-3=-6\sqrt{2y-5}$

Squaring both sides

$y^2+6y+9=72y-180$

Solve the equation for y

$y^2-66y+189=0\\\\(y-63)(y-3)=0\\\\y=3,63$

Check the solutions

For x = 63

$\sqrt{63+1}+\sqrt{2\cdot63-5}=3\\\\\sqrt{64}+\sqrt121}=3\\\\8+11\3\\\\19=3\Rightarrow \text{False}{$

Therefore, y = 63 is an extraneous solution.

Hence, y = 3 is the solution.

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Solve the given exponential equations. ( Ch-Exponents and radicals)

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