Question

solve √y+1+√2y-5=3 ​

Answer 1

Answer:

$\sqrt{y} + 1 + \sqrt{2y} - 5 = 3 \\ \\ = > \sqrt{y} + \sqrt{2y} - 4 = 3 \\ \\ \\ = > \sqrt{y} + \sqrt{2y} = 7 \\ \\ = > \sqrt{y} (1 + \sqrt{2} ) = 7 \\ \\ = > \sqrt{y} = \frac{7}{1 + \sqrt{2} } \\ \\ = > y = \frac{49}{ ({1 + \sqrt{2}) }^{2} } \\ \\ = > y = \frac{49}{1 + 2 + 2 \sqrt{2} } \\ \\ = > y = \frac{49}{3 + 2 \sqrt{2} }$

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Answer 2

Answer:

ok

Step-by-step explanation: