Math, asked by ayeshasyed9197, 4 months ago

solve (y-1) (3y+2) by correct method​

Answers

Answered by puneetlegend044
3

Step-by-step explanation:

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Answered by jeet8090youif7
3

Answer:

y(3y + 2) - 1(3y + 2) \\  = 3y {}^{2} +  2y - 3 y- 2 \\  = 3y {}^{2}   -  1y - 2 \\   = 3y {}^{2}   -  3y +2y - 2 \\  = 3y(y - 1) + 2(y - 1) \\  = (3y + 2) \\ and(y - 1) \\  \\ please \: mark \: the \: brainliest \: sir

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