Math, asked by ayeshasyed9197, 4 months ago

solve (y-1) (3y+2) by correct method

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Answered by puneetlegend044

Step-by-step explanation:

mark me as brainliest............

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Answered by jeet8090youif7

Answer:

$y(3y + 2) - 1(3y + 2) \\ = 3y {}^{2} + 2y - 3 y- 2 \\ = 3y {}^{2} - 1y - 2 \\ = 3y {}^{2} - 3y +2y - 2 \\ = 3y(y - 1) + 2(y - 1) \\ = (3y + 2) \\ and(y - 1) \\ \\ please \: mark \: the \: brainliest \: sir$

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solve (y-1) (3y+2) by correct method​

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solve (y-1) (3y+2) by correct method