Question

solve -y^2+3-x^2 where x=1 and y=2​

Answer 1

Step-by-step explanation:

-y^2 + 3-x^2

=> - (2)^2 + 3 - (1)^2

=> - 4 + 3 - 1

=> -1-1

=> -2

• Therefore, value of -y^2 + 3-x^2 when x =1 and y = 2 is -2

Answer 2

Answer:

How do you solve 2−3[x−2( x+1)]=x−[2−(x−3)]? ... x² + y2 - 6x + 8y =0 and x² + y2=a² havesame area