Math, asked by kundusundarshyam, 4 months ago

solve : ((y+2)/4)-((y-3)/3)=(1/2)

Answers

Answered by Anonymous
0

Answer:

589 is your answer.....

Answered by Anonymous
42

{ \mathfrak{ \huge \blue {\underline{Answer \colon}}}}

{ \rm{ \large{ y = 12}}}

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 { \bf{\huge{Solution:}}}

{ \rm{ \large{  \dfrac{(y + 2)}{4}  -  \dfrac{(y - 3)}{3}  =  \dfrac{1}{2} }}}

{ \rm{ \large{  \implies \dfrac{3 \{(y + 2) \} - 4 \{(y - 3) \}}{12}    =  \dfrac{1}{2} }}}

{ \rm{ \large{  \implies \dfrac{(3y + 6)  - (4y - 12) }{12}    =  \dfrac{1}{2} }}}

{ \rm{ \large{  \implies \dfrac{3y + 6 - 4y  + 12 }{12}    =  \dfrac{1}{2} }}}

{ \rm{ \large{  \implies \dfrac{( - y)   + 18 }{12}    =  \dfrac{1}{2} }}}

{ \rm{ \large{  \implies { 2 \{( - y)   + 18 } \}  = 1 \times {12}  }}}

{ \rm{ \large{  \implies {  - 2y + 36} =  {12}  }}}

{ \rm{ \large{  \implies {  - 2y } =  {12} - 36  }}}

{ \rm{ \large{  \implies {  - 2y } =   - 24  }}}

{ \rm{ \large{  \implies {  y } =    \dfrac{ - 24}{ - 2}   }}}

{ \rm{ \large{  \implies {  y } =    12 }}}

{ \rm{ \large{ \therefore y = 12}}}

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