Math, asked by riya3415, 2 months ago

solve

y+2/4 - y-3/3 = 1/3​

Answers

Answered by Anonymous
216

\Huge\sf\pink{{\rm{A}}nswe{\rm{R}}:}

\bf{{\underline{solution}}:}

sɪɴᴄᴇ, L. C. M ᴏғ ᴅᴇɴᴏᴍɪɴᴀᴛᴏʀ 4,3 ᴀɴᴅ 2 = 12

\sf\implies{12 x \:  {\dfrac{y + 2}{4}} - {12 x \:  {\dfrac{y  - 3} {3}}}} \:  = {12 x  \: {\dfrac{1} {2}}}

{ Mᴜʟᴛɪᴘʏɪɴɢ ᴇᴀᴄʜ ᴛᴇʀᴍ ʙʏ 12 }

\large{\tt\longmapsto{3(y+2) -4(y-3) = 6 }}

\large{\tt\longmapsto{3y + 6 - 4y + 12 = 6}}

\large{\tt\longmapsto{-y = -12 }}

\large{\tt\longmapsto{Y={\pink{\underline{\boxed{\bf 12}}}}}}

Answered by xxPRACHIxx
13

Answer:

solution

:

★sɪɴᴄᴇ, L. C. M ᴏғ ᴅᴇɴᴏᴍɪɴᴀᴛᴏʀ 4,3 ᴀɴᴅ 2 = 12★

\sf\implies{12 x \: {\dfrac{y + 2}{4}} - {12 x \: {\dfrac{y - 3} {3}}}} \: = {12 x \: {\dfrac{1} {2}}}⟹12x

4

y+2

−12x

3

y−3

=12x

2

1

✦{ Mᴜʟᴛɪᴘʏɪɴɢ ᴇᴀᴄʜ ᴛᴇʀᴍ ʙʏ 12 }✦

\large{\tt\longmapsto{3(y+2) -4(y-3) = 6 }}⟼3(y+2)−4(y−3)=6

\large{\tt\longmapsto{3y + 6 - 4y + 12 = 6}}⟼3y+6−4y+12=6

\large{\tt\longmapsto{-y = -12 }}⟼−y=−12

\large{\tt\longmapsto{Y={\pink{\underline{\boxed{\bf 12}}}}}}⟼Y=

12

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